Question

a ground is 120 M long and 85 metre wide. it has inside path of uniform width 3.5 all around it .the remaining part of the garden is covered by grass find the cost of covering the garden by grass at 50 paise per square.​

Answer 1

AnswEr :

⋆ Refrence of Image is in Attachment :

• DIMENSIONS OF INNER GROUND :

↦ Length = 120 - 2(3.5) = 120 - 7 = 113 m

↦ Breadth = 85 - 2(3.5) = 85 - 7 = 78 m

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• Area Required to Cover with Grass :

⇒ Area Required = Inner Area

⇒ Area Required = (l × b)

⇒ Area Required = (113 × 78)

⇒ Area Required = 8,814 m²

━━━━━━━━━━━━━━━━━━━━━━━━

• C O S T ⠀O F ⠀C O V E R I N G :

↠ Total Cost = Required Area × Rate

↠ Total Cost = 8,814 m² × 50 Paise

↠ Total Cost = 8,814 m² × Rs. 0.5

↠ Total Cost = Rs. 4407

∴ Cost of Covering of Garden is Rs. 4407

#answerwithquality #BAL

Answer 2

$\begin{lgathered} \red{\bf{Given}}\begin{cases}\underline{\footnotesize\sf{\star\:\:Dimensions\:of\:the\:ground}}\\\sf{Length(l)=120m }\\\sf{width(b)=85m}\\\sf{path \: widh=3.5m}\\ \sf{\footnotesize\bf{Find\:cost\:of\:grass\:@50paise/m^{2} }}</p><p>\end{cases}\end{lgathered}$

$\Large\bold\star\underline{\underline\textbf{Formula\:used}}$

• Area of Rectangle = Length × Width
• Since path is all Around the rectangle, that means both sides , if we subtract width of path from both sides we will get length and breadth of inside rectangle ..

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$\underline {\underline{\LARGE{{\bf{\green{S}}}{\mathfrak{o}}{\mathfrak{\orange{l}}}{\mathfrak{\red{u}}}{\mathfrak{\pink{t}}}{\mathfrak{\purple{i}}}{\mathfrak{\blue{o}}}{\mathfrak{\red{n}}}}}} : \:$

$\red{\textbf{Refer To image First : - - }} \:$

From image we can see that :---

→ ABCD is a bigger Rectangle

→ EFGH is a inside Rectangle with EF as length and FG as breadth ..

→ Length EF = AB - (AE + FB) = 120-(3.5+3.5) = 113m

Similarly,

→ Breadth FG = BC - (FB+GC) = 85-7 = 78m .

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$\begin{lgathered} \red{\bf{Given}}\begin{cases}\underline{\footnotesize\sf{\star\:\:Dimensions\:of\:New\:Rectangle\:EFGH}}\\\sf{Length(l)=113m }\\\sf{width(b)=78m}\end{cases}\end{lgathered} \:$

Hence

$Area_{\tiny RectangleEFGH} \: = 113 \times 78 \\ \\ Area_{\tiny RectangleEFGH} = \bold{\boxed{\large{\boxed{\orange{\small{\boxed{\large{\red{\bold{\:8814 {m}^{2} }}}}}}}}}} \:$

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And grass was only inside Rectangle Here ,

Hence,

$\textbf{Total cost of covering the area} \\ \textbf{By Grass is:-} = \\ \\ \red\longrightarrow \: \: 8814 \times 50 \: paise \\ \\ \red\longrightarrow \: 8814 \times \frac{1}{2} \\ \\ \red\longrightarrow \: \pink{\large\boxed{\boxed{\bold{Rs.4407}}}} \:$

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So, Total cost of Painted the grass was Rs.4407...

$\large\bold \red\star\underline\mathcal{Extra\:Brainly\:Knowledge:-}\red\star \:$

→ Perimeter of Rectangle = 2(length + Breadth)

→ Diagonal of Reactangle = √(l²+b²)

→ The diagonals of a rectangle bisect each other.

→ if path is outside the rectangle , we have to add 2×(width of path) to get, outside Rectangle Dimensions.....

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$\large\underline\textbf{Hope it Helps You.}$

#BAL