Question

A hammer of mass 500g, During at 50 m/s, striker a nail. The nails stops the hammer in a very short time of 0.15. what is the force of the nail on the hammer ? 

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Physics question

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Answer 1

$\huge{Answer}$

Given, mass of hammer

(m) = 500g = 0.5 kg

Initial Velocity of hammer

(u) = 50 m/s

Final velocity of hammer

(v) = Om/s

Duration (t) = 0. 015

Using second law of motion,

F = ma =

$m \frac{v - u}{t}$

F = 0.5 (0-50) / 0.01

= (0.5 × - 50) / 0.01

= 2,500 N

- ve sign shows the force of 2500

N acts in the opposite direction of motion.