Question

What volume of 3.0 M NaOH can be prepared with 80.0 g NaoH?​

Answer 1

Answer:

0.66L

Explanation:

Conc.=3.0M

No. of moles of NaOH=80/40

=2 moles

(40g is the molecular mass of NaOH)

Molarity= No. of moles of solute/ Volume of solution in litres(V)

3=2/V

V=2/3

V=0.66L

Answer 2

Answer: 2/3 = 0.67 L

Explanation: in the attached image