A heap of wheat is in the form of a cone whose diameter is 10.5 m and height 3 m. find its volume. This heap is to be covered by canvas to protect it from rain. Find the area of the canvas required.
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Hi ,
Dimensions of the conical shaped heap
Diameter = d = 10.5 m
Radius = r = d / 2
r = 10.5 / 2 = 5.25 m
i ) volume of the heap = volume of the cone
V = ( pi × r ^2 × h ) /3
= (22 / 7 ) × ( 5.25 )^2 × 3 / 3
= 86.625 cubic cm
ii ) let the slant height of the cone = l cm
l^2 = r^2 + h^2
= 3^2 + ( 5.25 )^2
= 9 + 27.5625
= 36.5625
Therefore ,
l = 6.046 ( approx)
The area of the canvas required to from rain
= curved surface area of the cone
= pi × r × l
= (22/ 7 ) × 5.25 × 6.046
= 697.62 / 7
= 99.66 cm^2
I hope this helps you.
***
Dimensions of the conical shaped heap
Diameter = d = 10.5 m
Radius = r = d / 2
r = 10.5 / 2 = 5.25 m
i ) volume of the heap = volume of the cone
V = ( pi × r ^2 × h ) /3
= (22 / 7 ) × ( 5.25 )^2 × 3 / 3
= 86.625 cubic cm
ii ) let the slant height of the cone = l cm
l^2 = r^2 + h^2
= 3^2 + ( 5.25 )^2
= 9 + 27.5625
= 36.5625
Therefore ,
l = 6.046 ( approx)
The area of the canvas required to from rain
= curved surface area of the cone
= pi × r × l
= (22/ 7 ) × 5.25 × 6.046
= 697.62 / 7
= 99.66 cm^2
I hope this helps you.
***
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