A hemisphere and a cone have equal bases. If their heights are also equal, then what is the ratio of their curved surfaces?
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Answer:
The Ratio of the curved surface area of hemisphere and cone = √2 : 1
Step-by-step explanation:
Given :
Base of a cone and hemisphere are equal then their Radius are also equal.
Radius and heights of the hemisphere and cone are same.
Let the radius of the hemisphere = radius of the cone = r
Height of the cone = radius of the hemisphere = r
Slant height of a cone, l = √r² + h²
l = √r² + r²
l = √2r²
l = r√2 ………….(1)
Curved surface area of hemisphere (S1) / Curved surface area of cone (S2) = 2πr² /πrl
S1/S2 = 2πr² /πrl
S1/S2 = 2r/l
S1/S2 = 2r/r√2
[From eq 1]
S1/S2 = 2/√2
S1/S2 = (2 × √2 )/(√2 × √2)
[On rationalising the denominator]
S1/S2 = 2√2/2
S1/S2 = √2/1
S1 : S2 = √2 : 1
Ratio of the curved surface area of hemisphere and cone = √2 : 1
Hence, the Ratio of the curved surface area of hemisphere and cone = √2 : 1
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