Question

A hemispherical bowl has a radius of 3.5 cm what would be the volume of water it would contain ?

Answer 1

Given that,

Radius of the Hemispherical Bowl = 3.5 cm

As we know that when it comes to find the quantity then we find Volume i.e. equal to the quantity that it contains. So we will find Volume.


$= > volume \: = \frac{2}{3} \pi \: {r}^{3}$
putting the values,

$= > volume \: = \frac{2}{3} \times \frac{22}{7} \times 3.5 \times 3.5 \times 3.5$

$= > \: volume \: = 89.83 \: or \: 90 \: {cm}^{3}$


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