a hemispherical bowl of inner diameter 10 cm has thickness 1cm .the cost of painting 1 sq. cm is rupees 2.find the cost of painting the vessel all over.
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Inner radius = r =10/2 = 5 cm
Outer radius = R = 5+1 = 6 cm thickness = 1 cm
Inner curved surface area = 2 π r²
Outer curved surface area = 2 π R²
On the base of hemispherical bowl, there is a flat ring area too.
Area of flat ring : π R² - π r²
Total surface area: 2 π r² + 2 π R² + π R² - π r²
= 3 π R² + π r²
= 3 *22/7 * 6² + 22/7 * 5² = 418 cm²
Cost of painting = area * price
= 418 * 2 = Rs 836
Outer radius = R = 5+1 = 6 cm thickness = 1 cm
Inner curved surface area = 2 π r²
Outer curved surface area = 2 π R²
On the base of hemispherical bowl, there is a flat ring area too.
Area of flat ring : π R² - π r²
Total surface area: 2 π r² + 2 π R² + π R² - π r²
= 3 π R² + π r²
= 3 *22/7 * 6² + 22/7 * 5² = 418 cm²
Cost of painting = area * price
= 418 * 2 = Rs 836
kvnmurty:
click on red heart thanks above pls
wrong..
this answer is correct. check it out yourself.
look u have written 2piR^2 but it will be 2piRh
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