A hemispherical tank, full of water, is emptied by a pipe at the rate of 25/7 litres per second. How much time will it take to empty half of the tank, if the diameter of the base of the tank is 3m?
Answers
To empty the half of the tank the pipe will take 16.5 minutes.
• Given data :
Flow rate of the pipe is 25/7 litres per second.
Diameter of the base of the tank is 3 metres.
• The radius of the base of the tank is :
= (Diameter/2)
= (3/2)
= 1.5 metres
• At first,we have to calculate the volume of the tank,by using the following mathematical formula :
= 2/3 × π × (radius)³
= 2/3 × 22/7 × (1.5)³
= 7.071 metre³ (approximately)
= 7071 litres [ Term of unit conversion is 1000 litres = 1 metre cube]
• So,the half capacity of the tank is :
= Total capacity of the tank / 2
= 7071/2
= 3535.5 litres
• Now,the pipe can
Empty 25/7 litres in = 1 second
1 litre in = 1×7/25 seconds
3535.5 litres in = 3535.5×7/25 = 989.94 seconds = 16.5 minutes (approximately)
So,the pipe will take approximately 16.5 minutes to empty the half of the tank. (Answer)
Answer:
16.5
Step-by-step explanation:
I hope it helps you ✌️✌️✌️
