Question

A hollow cone has base radius 10cm and height 24cm of the cone is un-rolled to form a sector of a circle the area of the sector is a

Answer 1

Answer:

Area of sector so formed is 817.14 sq-cm

Step-by-step explanation:

We know that Curved surface area of cone is

$\boxed{CSA_{cone} = \pi \: r \: l}$

where r is radius

and l is slant height .

In the given question, A hollow cone has base radius r =10cm and height h=24cm

$l = \sqrt{ {r}^{2} + {h}^{2} } \\ \\ l = \sqrt{100 + 576} \\ \\ l = \sqrt{676} \\ \\ l = 26 cm$

CSA of Cone =Area of sector

$= \frac{22}{7} \times 10 \times 26 \\ \\ = \frac{5720}{7} \\ \\ area \: of \: sector = 817.14 \: {cm}^{2}$

Hope it helps you.