Question

A hollow cylinder having external radius 8 cm and height 10 cm has a total
surface area of 338piecm². Find the thickness of the hollow metallic cylinder.



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Answer 1

Step-by-step explanation:

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Answer 2

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External Radius = R = 8 cm

Internal Radius = r

Height = 10 cm

TSA =338 π cm²

But TSA = Area of external cylinder (CSA)

+ Area of internal cylinder (CSA)

+ Twice Area of base (ring)

= 2πRh + 2πrh + 2π (R² - r²)

∴ 2π (Rh + rh + R² - r²) = 338π

Rh + rh + R² - r² = 169

➲ (10 × 8) + (r × 10) + 8² - r² = 169

➲ r² - 10r + 25 = 0

➲ (r - 5) ² = 0

➲ r = 5

Thickness lf metal = R - r = (8 - 5) cm = 3cm

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