a hollow metal sphere of internal and external radii 2cm and 4cm respectively is melted into a solid come of base 4cm. find the the height and slant height of the cone
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In the given sphere
R1 = 2cm and R2 = 4cm
We know that ,
Volume of sphere = 4 π ( R2cube - R1cube )
= 4 × 22 × [ 64 - 8]
3 × 7
= 4 × 22 × 56
21
= 704 cube.cm
3
If the sphere is now melted in a solid cone. Then also the volume will be the same
Therefore, the volume of cone = 704 by 3
Now,
the radius of base = 4cm
Volume of cone = π× Rsq× H
3
22 × 4 × H = 704
7 × 3 3
H = 704 × 7 × 3
88
H = 14 cm
(Slant height)^2 = H^2 + R^2
Slant height = ( 196 + 16) Sq root
= √212
Slant height = 14.56cm height = 14 cm
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