Question

A hollow metallic sphere of external and internal diameters 8cm and 4cm respectively is

melted to form a solid cone of base diameter 8cm. Find the height of the cone.​

Answer 1

•If solid of one shape is converted into solid of another shape, then Total volume of the solid to be converted =  Total volume of the solid into which the given solid is to be converted.

$\huge\bold\red{ANSWER:-}$

Given : Internal diameter of hollow sphere(d)= 4 cm.

Internal radius of hollow sphere (r) = 4/2= 2 cm

external diameter of hollow sphere (D) = 8 cm.

external radius of hollow sphere( R )= 8/2= 4 cm.

Volume of the Hollow sphere = 4/3π(R³ - r³)

Volume of the Hollow sphere = 4/3π(4³ - 2³)

Volume of the Hollow sphere = 4/3π(64 - 8)

Volume of the Hollow sphere = 4/3π(56) cm³

Diameter of the cone(d1) = 8 cm

radius of the cone( r1)= 8/2 = 4 cm

Let the height of the cone be h cm.

Volume of the cone = ⅓ πr1²h

= ⅓ π × 4² × h = 16πh/3

Volume of the cone = Volume of the hollow sphere

16πh/3 = 4/3π(56)

16h = 4 ×56

h = (4 × 56)/16

h = 56/4 = 14 cm

Hence, the height of the cone is 14 cm.

$\huge\bold\purple{THANKS.}$

Answer 2

Step-by-step explanation:

this is correct answer