A hollow sphere of mass 1 kg and radius 10 cm
is free to rotate about its diameter. If a force of
30N is applied tangentially to it, its angular
acceleration is (in rad/s2)
(1) 5000
(2) 450
(3) 50
(4) 5
pls explain how did we get 2/3 ..I have circled it
short and useless and will be reported
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1
Answer:
For the hollow sphere, the moment of Inertia is given by 2/3* M*R^2
Answered by
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Answer:
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