Math, asked by kkanchan0101, 11 months ago

A hollow wooden cylinder has a thickness of
1.5 cm. It is 28 cm long and has an outer radius
of 5.5 cm. Find the volume of oil it can hold.
ha of density​

Answers

Answered by yogiram12345
1

Answer:

Inner radius=5.5㎝=5.5㎝

Thickness=1.5㎝=1.5㎝

Outer radius=5.5+1.5=7㎝=5.5+1.5=7㎝

Volume of wood required=\pi \left( { R }^{ 2 }-{ r }^{ 2 } \right) \times h=π(R2−r2)×h

=\cfrac { 22 }{ 7 } \left( { 7 }^{ 2 }-{ \left( 5.5 \right)  }^{ 2 } \right) \times 28=722(72−(5.5) 2)×28

=88(49-30.25)=88(49−30.25)

=1650㎤=1650㎤

Answered by tarnav601
1

Answer:

inner radius = 5.5cm

Thickness = 1.5 cm

outer radius= 5.5 + 1.5 =7cm

Volume of Wood Required= π (R^2 - r^2)× h

=22/7 ( 7^2 - (5.5)^2 ) ×28

=88 ( 49 -30.25 )

=1650cm^2

Step-by-step explanation:

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