A hollow wooden cylinder has a thickness of
1.5 cm. It is 28 cm long and has an outer radius
of 5.5 cm. Find the volume of oil it can hold.
ha of density
Answers
Answered by
1
Answer:
Inner radius=5.5㎝=5.5㎝
Thickness=1.5㎝=1.5㎝
Outer radius=5.5+1.5=7㎝=5.5+1.5=7㎝
Volume of wood required=\pi \left( { R }^{ 2 }-{ r }^{ 2 } \right) \times h=π(R2−r2)×h
=\cfrac { 22 }{ 7 } \left( { 7 }^{ 2 }-{ \left( 5.5 \right) }^{ 2 } \right) \times 28=722(72−(5.5) 2)×28
=88(49-30.25)=88(49−30.25)
=1650㎤=1650㎤
Answered by
1
Answer:
inner radius = 5.5cm
Thickness = 1.5 cm
outer radius= 5.5 + 1.5 =7cm
Volume of Wood Required= π (R^2 - r^2)× h
=22/7 ( 7^2 - (5.5)^2 ) ×28
=88 ( 49 -30.25 )
=1650cm^2
Step-by-step explanation:
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