Question

a horizontal circular turnable rotates about its centre at the uniform rate of 120revolutions per minutes.find the gratest distance from the centre at which a small body will remain stationary relative to the turnable,if the coefficient of static friction between turnable and body is 0.80

Answer 1

Answer:

Here for the body to remain stationary the centrifugal force should be less than of equal to maximium static friction. mw^2 r should be less than or equal to fsN. is m(2π × 120÷60) ^2 r= 0.80× m × 10. ie (2π ×2) ^2 r=8 16π^ 2 r = 8.r= 1/2π^2.