Question

A hot water system consists of a cylindrical pipe of length 14m and diameter 5cm find the total radiating surface of hot water system

Answer 1

for this we find the CSA of the cylinder
radius = 5/2
=2.5
convert into cm=1400
CSA=2πrh
=2×22/7×2.5×1400
=2×22×2.5×200
=44×500
=22000cm²
=220m²

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Answer 2

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✴.Radius[R] = $\frac{diameter}{2} ={5}{2}$ =2.5Cm.

Length of the pipe = height =14m

Radiating surface = 2${\phi}$ rh

2${\phi}$ $\frac{22}{7}$ × 2.5 × 1400

=22000${cm}^3$

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