Question

A How much current is drawn by a bulb rated 100 W and designed for a mains supply of 250 V when operated normally?

Answer 1

Answer:

Rating of bulb is given as 220 V,100W i.e V

b

=200 V and P

b

=100 W

Thus resistance of bulb R=

P

b

V

b

2

=

100

(200)

2

=400 Ω

Equivalent resistance of 5 bulbs connected in series R

s

=5R=5×400=2000Ω

Supply voltage V

s

=200 V

So, current in the circuit I=

R

s

V

s

=

2000

200

=0.1 A

Answer 2

Answer:

Explanation:

We know that

Watt=voltage*current

100W/250v=current

0.4amps

Hope it helps

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