A=iAcosx+jBsinx how to find perpendicular to this vector?
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Answer:
-i B sin x + j A cos x
Step-by-step explanation:
In general, given any point ( a, b ) in the plane, rotating this 90 degrees anticlockwise around the origin takes it to ( -b, a ).
So the vector
-b i + a j
is perpendicular to the vector
a i + b j
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