Question

A is thrice as good a workman as b and therfore is able to finish a piece of work in 60 days less than

b.working together they can do it in

Answer 1

HEY DEAR . ✌

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Assume number of days taken by A =x days, then number of days taken by B =3x days (as A is thrice as efficient as B).

According to the question,

3x - x = 60 days, hence x = 30 days

SO, number of days taken by A = 30 days, and number of days taken by B = 90 days

Assume total units of work = LCM (30 , 90) units = 90 units

So, work done by A in one day = (90/30) = 3 units per day AND

work done by B in one day = (90/90) = 1 unit per day.

HEnce total units done by both A and B together in one day = 4 units per day

So, total number of days taken by both of them = Total work / Number of units done in one day = 90 / 4 = 22.5 days.

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Answer 2

Hey...!!! :))
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Solution :- please see the attachment

$22 \times \frac{1}{2}$
days Ans

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