Question

a jogger jobs alone one length and breadth a rectangular park.the dimensions of park are 150m×120m,then find distance $ displacement of jogger.

Answer 1

total distance =150+120=270
total displacement =
${ac}^{2} = {ab}^{2} + {bc}^{2}$
${ac}^{2} = 22500 + 14400 = 36900$
ac=
$\sqrt{36900 = 19.20}$
this is the right answer

Answer 2

thus the distance covered by jogger is 270 m and the displacement covered by Jogger is 192.0 9 m.
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