a jogger runs 5.0 km on a straight trail 5.0 km on a straight trail at an angle of 60 degrees south west. what is the southern component of the run rounded to the nearest tenth of a kilometer?
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Answered by
2
Heya friend here is your answer
The components are the sides S and W of a right triangle with SW = 5 km as the hypotenuse. It helps to sketch out these types problems.
Using the 60°south of west angle would make W adjacent and S opposite to the angle. using SOH CAH TOA
sin(60) = S/5
5*sin(60) = S
5*√(3)/2 = S
4.3 km = S
The components are the sides S and W of a right triangle with SW = 5 km as the hypotenuse. It helps to sketch out these types problems.
Using the 60°south of west angle would make W adjacent and S opposite to the angle. using SOH CAH TOA
sin(60) = S/5
5*sin(60) = S
5*√(3)/2 = S
4.3 km = S
Answered by
0
Answer:
I believe it's -4.3
Explanation:
sorry, if I'm wrong but I hope this is right!
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