Question

A Joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.

Answer 1

Step-by-step explanation:

The area of sheet required is 5500cm²

Answer 2

✬ Sheet required = 5500 cm² ✬

Step-by-step explanation:

Given:

• Base radius of right circular cone is 7 cm.
• Height of right circular cone is 24 cm.

To Find:

• What is the area of sheet required to make 10 caps?

Solution: Here, Radius and Height of the circular cone are given , so we have to find the slant height of the cone .

★ Slant height ( l ) = √Radius² + Height ²

$\implies{\rm }$ l = √(7)² + (24)²

$\implies{\rm }$ l = √49 + 576

$\implies{\rm }$ l = √625

$\implies{\rm }$ l = √25 x 25

$\implies{\rm }$ l = 25 cm

So, The Slant height of right circular cone is 25 cm. Now we have to find the curved surface area of the cone.

★ CSA of cone = πrl ★

$\implies{\rm }$ CSA = (22/7 x 7 x 25) cm²

$\implies{\rm }$ CSA = (22 x 25) cm²

$\implies{\rm }$ CSA = 550 cm²

➣ Curved Surface area of one circular cap = 550 cm²

∴ CSA of 10 caps = ( 550 x 10 ) = 5500 cm²

Hence, The area of sheet required to make 10 caps is 5500 cm².