Question

A journey of 192 km takes 2 hours less by a fast train than by a slow train. if the average speed of the slow train be 16 kmph less than that of fast train, what is the average speed of the faster train

Answer 1

Let the speed of the fast train be X

The speed of the slow train would be X - 16

Time taken by the fast train is 192 / X

Time taken by the slow train is 192 / X -16

The difference between the time taken by the two trains is 2 hours

Hence [192 / X-16]  - 192 / X = 2

Solving this would result in  X^2 - 16X + 1536 = 0

Hence X = 48kmph which is the speed of the fast train.

Hence the speed of the slow train is 48 - 16 = 32 kmph

Answer 2

Step-by-step explanation:

48 speed of a first train

48-16 32 speed of second train