A juggler throws a beanbag into the air with a speed of 1.0 \dfrac{\text m}{\text s}1.0 s m 1, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. How long does it take for the beanbag to reach its maximum height?
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Explanation:
A juggler throws a beanbag into the air with a speed of 1.0
The initial speed is 1 m/s
The beanbag will reach to its maximum height
At the maximum height the speed equal to zero
The final speed is zero
The acceleration of gravity = -9.8 m/s
We need to find how long it takes for the beanbag to reach its maximum
height
Lets use the rule: v = u + gt, where v is the final speed, u is the initial
velocity, t is the time and g is the acceleration of gravity
v= 0 , u = 1 , g = -9.8
0 = 1 - 9.8 t
Add two sides by 9.8 t
9.8 t = 1
Divide both sides by 9.8
t = 5/49 seconds
It takes for the beanbag 5/49 seconds to reach its maximum height
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