Question

a juggler throws balls innto air. he throws one whenever the previous one is at its highest point. how high do the balls rise if he throws n balls each second? acceleration due to gravity is g.

Answer 1

Hey there !!!

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Juggler throws the ball into the air with ball having  initial velocity = u

At the highest point of its path velocity will be zero as at maximum height velocity =0

So final velocity=0

According to question juggler throws a ball each second so for "n" balls 
time taken to reach highest position (t)= 1/n 

    v=u+gt

     0=u-g/n

    -u=-g/n

    u=g/n


S= ut-gt²/2

S=u/n-g/2n²

But u=g/n

S= g/n²-g/2n²

S=g/2n²

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Hope this helped you................