A kone is cut into two parts by a horizontal plane passing through the midpoint of its Axis find the ratio of the volumes of the upper part and the cone
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When the cone is cut like said in the question, let us suppose the radius of small cone is r and of original cone is R. Let us suppose their heights are h and H respectively.
These two cones will be similar
Hence r/R = h/H = 1/2
Now ratio of volume of small cone and big cone will be
?r2h/?R2H
= (r2/R2)(h/H)
= 1/8
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