A ladder placed against a wall such that it reaches the top of the wall of height 10 m and the ladder is inclined at an angle of 75 degrees. Find how far the ladder is from the foot of the wall. (Sketch a diagram)
Answers
Answered by
1
Answer:
Consider
AB as the well and ACV as the ladder whose foot C is 1.5 m away from B,
Let us take AB=x m and angle of inclination is 60
0
,
In right △ABC
tanθ=
CB
AB
Substituting the values,
⇒tan60
o
=
1.5
x
⇒
3
=
1.5
x
By cross multiplication,
⇒x=
3
×1.5=1.732×1.5
x=2.5980≈2.6
Hence, the height of the wall is 2.6m.
solution
Explanation:
Similar questions