A lady has 25 paise and 50 paise in coins in her purse. if in all she has 40 coins to talking rupees 1250, find the number of coins of each type she has
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HELLO DEAR !!!!....
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LET the number of 25 paisa coins be x and 50 paisa coins be y
so , 25x +50y = 1250 - - - - (1) ( converting values in paisa)
and x +y = 40. - - - - - (2)
so x = 40 - y
PUTTING the value of x in equation (1)
so, 25(40 - y) + 50y = 1250
1000 - 25y + 50y = 1250
25y = 1250 -1000
25y = 250
y = 10
SO the number of coins 50 paisa is 10 now putting this value of y in eq (2)
x + y = 40
x + 10= 40
and x =30
So , 25 paise coins = (x) = 30
50 paise coins = (y) = 10
__________________________
HOPE IT HELPS U DEAR !!!!
Cheers
# Nikky ✌✌
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LET the number of 25 paisa coins be x and 50 paisa coins be y
so , 25x +50y = 1250 - - - - (1) ( converting values in paisa)
and x +y = 40. - - - - - (2)
so x = 40 - y
PUTTING the value of x in equation (1)
so, 25(40 - y) + 50y = 1250
1000 - 25y + 50y = 1250
25y = 1250 -1000
25y = 250
y = 10
SO the number of coins 50 paisa is 10 now putting this value of y in eq (2)
x + y = 40
x + 10= 40
and x =30
So , 25 paise coins = (x) = 30
50 paise coins = (y) = 10
__________________________
HOPE IT HELPS U DEAR !!!!
Cheers
# Nikky ✌✌
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Heya.....✋
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