Question

a lady has only 25 paisa and 50 paisa coin in her purse . if she has 50 coins in all totalling Rs.19.50 how many coins of each type does she have .​

Answer 1

Step-by-step explanation:

Let x and y be the number of 50-paisa and 25-paisa coins respectively. Then x + y = 50 ……….(i) 0.5x + 0.25y = 19.50 ………(ii) Multiplying (ii) by 2 and subtracting it from (i), we get 0.5y = 50 - 39 ⇒ y = 11/0.5 = 22 Subtracting y = 22 in (i), we get x + 22 = 50 ⇒ x = 50 – 22 = 28 Hence, the number of 25-paisa and 50-paisa coins is 22 and 28.

Answer 2

Step-by-step explanation:

Let x and y be the number of 50-paisa and 25-paisa coins respectively. Then x + y = 50 ……….(i) 0.5x + 0.25y = 19.50 ………(ii) Multiplying (ii) by 2 and subtracting it from (i), we get 0.5y = 50 - 39 ⇒ y = 11/0.5 = 22 Subtracting y = 22 in (i), we get x + 22 = 50 ⇒ x = 50 – 22 = 28 Hence, the number of 25-paisa and 50-paisa coins is 22 and 28 respectively.Read more on Sarthaks.com - https://www.sarthaks.com/132281/lady-has-only-paisa-coins-and-paisa-coins-her-purse-if-she-has-50-coins-in-all-totaling-rs-19-50