Question

A lady went shopping and spent half of what she had on buying hankies and gave a rupee to a begger waiting outside the shop. She spent half of what was left of what was left on a lunch and followed that up with a two rupee itp. She spent half of the remaining amount on a book and three rupees on bus fare. When she reached home, she found that she had exactly one rupee left. How much money did she start with?

Answer 1

Answer:

Let starting money be x.

Amount she spent on hankies will be $\frac{x}{2}$

After that she would be left with x- $\frac{x}{2}$ which would be $\frac{x}{2}$

Now she gave the beggar 1rs. She would be left with  $\frac{x}{2}$-1

She spent half of remaining money on lunch followed by a tip. So she spent,

$\frac{x-2} {\frac{2} 2} -2$

Half of that remaining amount was spent on a book and 3rs was spent on the bus fare. $(\frac{x-2} {\frac{2} 2} -2) \frac{1}{2}-3$

She has 1rs left. so,

$(\frac{x-2} {\frac{2} 2} -2) \frac{1}{2} -3$=1

$\frac{x-2} {\frac{2} 2} -2$=8

$\frac{x-2} {\frac{2} 2}$=10

$\frac{x-2}{2}$=20

x-2=40

x=42

Hence she had 42 rupees.

Answer 2

Answer:

42rs

Step-by-step explanation:

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