Question

A lamp rated 60 w and an electric iron rated 800w are used for 6 hours everyday . Calculate the total energy consumed in 30 days.

Answer 1

total energy consuming in one day is 800+60=860 now in 30 days it will consume 860x30x6=154800

Answer 2

$\fbox{\texttt{\green{Answer:}}}$

Energy consumed in 30 days = 154.8 kWh

$\fbox{\texttt{\pink{Given:}}}$

Power of lamp = 60W

Power of electric iron = 800W

Time operated per day (both appliances) = 6 hours

$\fbox{\texttt{\blue{To\:find:}}}$

Total energy consumed in 30 days.

$\fbox{\texttt{\red{How\:to\:find:}}}$

We know, E = P × t (Energy = power × time)

➪ Energy consumed by lamp, $\bold{E_1}$ = 60 × 6 = 360 watt-hour = 0.36 kWh

➪ Energy consumed by electric iron, $\bold{E_2}$ = 800 × 6 = 4800 watt-hour = 4.8 kWh

$\therefore$ Total energy consumed $\bold{E=E_1+E_2}$

= 0.36 + 4.8 = 5.16 kWh

$\therefore$ Energy consumed in 30 days = 5.16 × 30 = 154.8 kWh