A length of a rectangle is 7m more than its bredth.if the perimeter 50m.find the length and breadth of the rectangle
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Answered by
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Let breadth = x
Given, length = breadth + 7
i.e., length = x+7
Permieter = 2(l+b)
Permeter = 50m
i.e., 2(l+b) = 50
2(x+7+x) = 50
2(2x+7) = 50
2x+7 = 50/2
2x + 7= 25
2x = 25-7
2x = 18
x = 9
Therefore, breadth = x= 9m
Length = x+7 = 16 m
Given, length = breadth + 7
i.e., length = x+7
Permieter = 2(l+b)
Permeter = 50m
i.e., 2(l+b) = 50
2(x+7+x) = 50
2(2x+7) = 50
2x+7 = 50/2
2x + 7= 25
2x = 25-7
2x = 18
x = 9
Therefore, breadth = x= 9m
Length = x+7 = 16 m
AlienRapper:
Hope it helped!
Answered by
1
Hii dear here is your answer......
let breadth=x
so according to question
●length=x+7
◆perimeter of rectangle=2(l+B)
●Perimeter =50m
◆50=2(l+B)
◆25=(x+x+7)
◆25=2x+7
◆25-7=2x
◆18=2x
◆x=18/2=9m
◆length =x+7
◆9+7=16
◆so ,length =16m and breadth=9m
hope it helps you....☺☺
let breadth=x
so according to question
●length=x+7
◆perimeter of rectangle=2(l+B)
●Perimeter =50m
◆50=2(l+B)
◆25=(x+x+7)
◆25=2x+7
◆25-7=2x
◆18=2x
◆x=18/2=9m
◆length =x+7
◆9+7=16
◆so ,length =16m and breadth=9m
hope it helps you....☺☺
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