the altitude of a triangular field is1/3 times its base .if the cost of cultivating the field at rs100 per m^2 is rupey 29990.94 find the base and altitude of the field
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let the base =x
so altitude =1/3*x
Area of triangle=1'2*b*h
Area!=1/2*x/3*x
Area=x*x/6
cost of cultivating =100/29990.04
=1/299.904
Area=cost of cultivating
x*x/6=1/299.904
x*x=6/299.904
x*x=1/49.984
x=7.06
altitude =1/3*x
=1*7.06/3
=2.3533
base=x
=7.06
so altitude =1/3*x
Area of triangle=1'2*b*h
Area!=1/2*x/3*x
Area=x*x/6
cost of cultivating =100/29990.04
=1/299.904
Area=cost of cultivating
x*x/6=1/299.904
x*x=6/299.904
x*x=1/49.984
x=7.06
altitude =1/3*x
=1*7.06/3
=2.3533
base=x
=7.06
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4
Answer:
eska answer Galt ha eska answer b =42.4m h =14.14m yaha answer ha
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