A letter Á' is constructed of a uniform wire of resistance 1 ohm per cm . the side of letter are 6 cm each and the cross piece in the middle is 3cm long . calculate the resistance between the ends of the legs.
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I have redrawn the “A” in a more logical fashion.
R2 + R3 are in series. The calculation for this combination is (R2+R3) = 20 Ohms. In effect we have a single 20 Ohm resistor which we’ll call R23.
R 23 is in parallel with R4. The calculation for this combination is (R23xR4)/R23+R4) = (20 x 10)/(20+10) = 200/30 = 6.66 (recurring). Call it 6.67. So the middle combination of R2, R3, R4 = 6.67 Ohms.
This is in series with R1 and R5 so the total resistance is 10 + 6.67 + 10 Ohms = 26.67 Ohms.
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R2 + R3 are in series. The calculation for this combination is (R2+R3) = 20 Ohms. In effect we have a single 20 Ohm resistor which we’ll call R23.
R 23 is in parallel with R4. The calculation for this combination is (R23xR4)/R23+R4) = (20 x 10)/(20+10) = 200/30 = 6.66 (recurring). Call it 6.67. So the middle combination of R2, R3, R4 = 6.67 Ohms.
This is in series with R1 and R5 so the total resistance is 10 + 6.67 + 10 Ohms = 26.67 Ohms.
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Answer:
[le l.undu.re] muh me le
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