Math, asked by SachiSah, 5 hours ago

A lift in a mine moves down 24metre in 87 minutes . If it moves in uniform rate , find at what distance below the surface, it will be after 6mins. If the lift starts from a height 10metre above the ground , find how deep the lift will go from the surface after 70 minutes.​

Answers

Answered by shreyadw6
3

Step-by-step explanation:

Hence, after 70 mins the lift goes 9.32m deep. So, after 6 min, the lift is 0.276x6 = 1.656m below. Then, the rest 70-36.232 = 33.768 min is spent below. So, it moves 0.276x 33.768 = 9.32m at this time.

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