A line p, meets two concentric circles , with same centre O, at A, B, C and D as shown in the figure .prove that triangle OAB congruent triangleODC.
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Step-by-step explanation:
We know that, OA=OD and OB=OC.
They are radius of respective circles.
In ΔOBC, we know that OB=OC, so ∠OBC=∠OCB
∴∠OCD=∠OBA
In ΔOAD, we know that OA=OD, so ∠OAD=∠ODA
Since, ∠OCD=∠OBA and ∠OAD=∠ODA, we get ∠AOB in ΔOAB is equal to ∠COD in ΔOCD.
∴ From SAS congruency, we can say that ΔOAB and ΔOCD are congruent.
So, AB=CD.
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