Math, asked by kittynoir1226, 1 year ago

A line, y = mx + b, passes through the point (1, 6) and is parallel to y =4x + 6
What is the x and y intercept of the line?

Answers

Answered by HappiestWriter012
31
Given that,

A line y = mx + b passes through the point ( 1, 6)

So, 6 = m + b.

Also, Given that, It is parallel to y = 4x + 6.

We know that, Slope of parallel lines is equal. Hence,

Slope of "6 = m + b " = Slope of " y = 4x + c"

[ Slope of line in form of y = mx + c is m]

Hence, m = 4.

Now,

6 = m + b

6 = 4 + b

b = 2.

Therefore, The line is, y = 4x + 2.

Y - Intercept :

y = 4x + 2

y = 4(0)+2 = 2

X - Intercept,

y = 4x + 2

0 = 4x + 2

4x = - 2

x = - 2/4

Therefore, The X-intercept and Y - intercept are - 1/2 , 2 respectively.

Anonymous: pleaseeeeeeeeeee
amitnrw: there is mistake in last step after 4x = -2 , x should be = -2/4 = -1/2 not -2
Answered by amitnrw
7

Answer:

x intercept = -1/2

y intercept = 2

Step-by-step explanation:

A line, y = mx + b, passes through the point (1, 6) and is parallel to y =4x + 6  

What is the x and y intercept of the line?

y = mx + b parallel to y =4x + 6  

so m = 4

y = 4x + b

it passed through (1,6)

6 = 4(1) + b

b = 2

=>

y intercept

y = 4x + 2

for x = 0

y = 4*0 + 2

y = 2

x intercept

for y = 0

0 = 4x + 2

=> x = -2/4

=> x = -1/2

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