A line, y = mx + b, passes through the point (1, 6) and is parallel to y =4x + 6
What is the x and y intercept of the line?
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31
Given that,
A line y = mx + b passes through the point ( 1, 6)
So, 6 = m + b.
Also, Given that, It is parallel to y = 4x + 6.
We know that, Slope of parallel lines is equal. Hence,
Slope of "6 = m + b " = Slope of " y = 4x + c"
[ Slope of line in form of y = mx + c is m]
Hence, m = 4.
Now,
6 = m + b
6 = 4 + b
b = 2.
Therefore, The line is, y = 4x + 2.
Y - Intercept :
y = 4x + 2
y = 4(0)+2 = 2
X - Intercept,
y = 4x + 2
0 = 4x + 2
4x = - 2
x = - 2/4
Therefore, The X-intercept and Y - intercept are - 1/2 , 2 respectively.
A line y = mx + b passes through the point ( 1, 6)
So, 6 = m + b.
Also, Given that, It is parallel to y = 4x + 6.
We know that, Slope of parallel lines is equal. Hence,
Slope of "6 = m + b " = Slope of " y = 4x + c"
[ Slope of line in form of y = mx + c is m]
Hence, m = 4.
Now,
6 = m + b
6 = 4 + b
b = 2.
Therefore, The line is, y = 4x + 2.
Y - Intercept :
y = 4x + 2
y = 4(0)+2 = 2
X - Intercept,
y = 4x + 2
0 = 4x + 2
4x = - 2
x = - 2/4
Therefore, The X-intercept and Y - intercept are - 1/2 , 2 respectively.
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Answered by
7
Answer:
x intercept = -1/2
y intercept = 2
Step-by-step explanation:
A line, y = mx + b, passes through the point (1, 6) and is parallel to y =4x + 6
What is the x and y intercept of the line?
y = mx + b parallel to y =4x + 6
so m = 4
y = 4x + b
it passed through (1,6)
6 = 4(1) + b
b = 2
=>
y intercept
y = 4x + 2
for x = 0
y = 4*0 + 2
y = 2
x intercept
for y = 0
0 = 4x + 2
=> x = -2/4
=> x = -1/2
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