Question

A liquid having coefficient of viscosity 0.02 decapoise is filled in a container of cross sectional area 20 m^2 if viscous drag between two adjacent layers in flowing is 1 n the velocity gradient is?

Answer 1

We know, $\bf{F=\mu A\left(\frac{dv}{dx}\right)}$
where , F is viscous drag, $\mu$ is coefficient of viscosity , A is cross sectional area and dv/dx is velocity gradient.


given, F = 1 N 
µ = = 0.02 decapoise = 0.02 Ns/m²
A = 20 m^2

so, (dv/dx) = F/(µA) = 1 N / (0.02 Ns/m^2 * 20 m^2) 
(dv/dx) = 2.5 s^-1

hence, velocity gradient = 2.5 s^-1

Answer 2

We know,

where , F is viscous drag, is coefficient of viscosity , A is cross sectional area and dv/dx is velocity gradient.

given, F = 1 N 

µ = = 0.02 decapoise = 0.02 Ns/m²

A = 20 m^2

so, (dv/dx) = F/(µA) = 1 N / (0.02 Ns/m^2 * 20 m^2) 

(dv/dx) = 2.5 s^-1

hence, velocity gradient = 2.5 s^-1

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