A liquid is filled in a spherical container of radius r till a height h. At this position the liquid surface at the edges is also horizontal. The contact angle is
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Hii dear,
◆ Answer- cosinv[(R-h)/R]
◆ Explanation-
[Refer to the figure]
Consider a sphere of radius R filled with fluid upto height h.
Let θ be the angle of contact of the fluid.
From the figure,
sin(π/4-θ) = (R-h)/R
cosθ = (R-h)/R
Taking inverse on both sides-
θ = cosinv[(R-h)/R]
Contact angle is cosinv[(R-h)/R].
Hope that is useful...
◆ Answer- cosinv[(R-h)/R]
◆ Explanation-
[Refer to the figure]
Consider a sphere of radius R filled with fluid upto height h.
Let θ be the angle of contact of the fluid.
From the figure,
sin(π/4-θ) = (R-h)/R
cosθ = (R-h)/R
Taking inverse on both sides-
θ = cosinv[(R-h)/R]
Contact angle is cosinv[(R-h)/R].
Hope that is useful...
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