A cube of edge length 10 cm is just balanced at the interface of two liquids
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Two liquids are A and B.The B has only 6cm and liquid A contains only 4cm
The gravity specified for liquid A and Liquid B is 0.6 and 0.4 the mass of cube will be :-
The force is balanced in vertical direction that is Mg=(pVg)1+(pVg)2.So the value of M= (0.4 g/ml)600cm^3 + (0.6 g/ml)(400 cm^3) since 1 ml = i cm^3
And so the answer is 480gm which is the mass of the cube.
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