Question

A little help here please....​

Answer 1

HOLA !!!

ANSWER :-

〽DISTANCE :-

Formula to find the circumference : 2πr

$= 2\pi \: 400$

(Given 400 m as radius)

Distance travel is three fourth of the circumference .

Hence , distance ->

$(3 \div 4)2\pi \: \times 400$

$= 600\pi \: metres$

〽DISPLACEMENT :-

△AOB is a right angle triangle.

By Pythagoras theorem ,

(AB)^2=(AO)^2+(BO)^2

(AB)^2=400^2+400^2

(AB)^2=160000+160000

(AB)^2=320000

AB=√320000

AB=565.68 metres

HOPE IT HELPS UHH #CHEERS

Answer 2

R=400 m

distance=total original path covered

=2πR-πR/2

=3πR/2

=3*3.14*400/2

=1884 m

Displacement=shortest distance between the two points

by pythagoreas theorem

AB²=R²+R²

AB=√2R

=1.414*400

=565.6 m

( I answered your question cause your handwriting is verrrry nice...XD)