Physics, asked by raeesah6253, 10 months ago

A long circular aluminium rod of thermal conductivity 240 w/m.K is attached at one end to a heated wall and transfers heat by convection to a cold fluid. If the diameter of the rod is tripled, the rate of heat removal (in %) increases by

Answers

Answered by sarachougule
0

Answer:

sorry ma lum Nahi ha . sorry about this

Answered by mindfulmaisel
0

The rate of heat removal increases by 800%

According to the formula of convection of heat, the amount of heat transfer,

Q = H_{c\\} A (T_{Hot} - T_{Cold})

Where, T = Temperature

A = Area of the cross section = πd²/4 , d = diameter of the rod

H_{c} = Convective heat transfer coefficient or, thermal conductivity = 240 W/m.K (given)

Suppose, the initial diameter of the rod = d

The final diameter of the rod = 3d

Q ∝ d²

Q₁/Q₂ = (d₁/d₂)²

⇒ Q₁/Q₂ = 1/9

∴ Q₂/Q₁ = 9

⇒ (Q₂/Q₁) - 1 = 9 - 1

⇒ (Q₂ - Q₁/Q₁) = 8

\frac{Q_{2}-Q_{1}  }{Q_{1}} × 100% = 800%

∴ The rate of heat removal is increased by 800%.

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