A long solenoid is formed by winding 20 turns/cm. The current necessary to produce a magnetic field of 20 millitesla inside the solenoid will be approximately (\frac{{{\mu }_{0}}}{4\pi }={{10}^{-7}}\,tesla-metre/ampere)
[MP PMT 1994]
A) 8.0 A B) 4.0 A C) 2.0 A D) 1.0 A
Answers
Answered by
5
B=u.NI
Usethis formula
Take 1 million tesla = 0.001 tesla
Answered by
29
Answer:
8.0A
Explanation:
n=20cm
B=20mT
I=B/mu.n
20×10^-3/4π×10^-7×20×10^2
=8.0A
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