Question

A machine of Mechanical advantage= 6 is used for a load of 120 kgf. Find the required effort *​

Answer 1

Given

A machine of mechanical advantage = 6 is used for a load of 120 kgf

To Find

Required effort

Solution

We know that

$\rm \longrightarrow M.A=\dfrac{F_{o}}{F_{i}}$

Here

• $\rm M.A$ = Mechanical Advantage
• $\rm F_{o}$ = Output Force
• $\rm F_{i}$ = Input Force

According to the question

We are asked to find the required effort

Hence

We must find input Force ($\rm F_{i}$)

Therefore

$\rm \longrightarrow F_{i}=\dfrac{F_{o}}{M.A}$

Given that

A machine of mechanical advantage = 6 is used for a load of 120 kgf

Hence

• $\rm M.A$ = 6
• $\rm F_{o}$ = 120 kgf

Substituting the values

We get

$\rm \longrightarrow F_{i}=\dfrac{120}{2} \ kgf$

Therefore

$\rm \longrightarrow F_{i}=20 \ kgf$

Hence

Required effort = 20 kgf