A magnetic flux of 8 × 10−4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.
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Answer:
¢=LI
n¢=LI
n=200turns
L=n¢/I
L=200*8*10/4
L=4*16²A
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