Question

The current in a solenoid of 240 turns, having a length of 12 cm and a radius of 2 cm, changes at a rate of 0.8 A s−1. Find the emf induced in it.

Answer 1

di

emf induced e = L

dt

L=HoN(Tr2)

E= HoN(Tr) di

dt

4Tt x 10x (240)2 x (T)(2 x 102) x 0.8

12 x 10-2=6.14×10

−4

V