The current in a solenoid of 240 turns, having a length of 12 cm and a radius of 2 cm, changes at a rate of 0.8 A s−1. Find the emf induced in it.
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di
emf induced e = L
dt
L=HoN(Tr2)
E= HoN(Tr) di
dt
4Tt x 10x (240)2 x (T)(2 x 102) x 0.8
12 x 10-2=6.14×10
−4
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