Math, asked by Annop, 1 year ago

A man baught a certain number mangoes at Rs 14.40 p and gain 44p by selling some of them for Rs 8 . Find at least how many mangoes he was left with?


Annop: please any one solution this question plzzz

Answers

Answered by VEDULAKRISHNACHAITAN
14

Answer:

47.5% of mangoes which he man had initially bought

Step-by-step explanation:

Hi,

Let N be the initial number of mangoes the man had bought,

Given total cost of N mangoes = Rs 14.40 p---(1)

Let 'x' be the number of mangoes man had sold

Given that by selling x mangoes at Rs 8, man had gained 44 p

So, Cost price of x mangoes = Selling Price - Gain

= Rs  8 - 44 p

= Rs 7. 56 p----(2)

From (1) and (2),

Cost Price of N mangoes = Rs 14.4

Cost Price of x mangoes = Rs 7.56

So, x/N = 7.56/14.4 = 21/40

So, x = 21N/40

After selling x mangoes, there will be (N - x ) mangoes left

= N - 21N/40

= 19N/40

Percentage of mangoes left would be 19N/40N*100 = 47.5% .

Hence , 47.5% of the mangoes which he had initially bought are left.

Hope, it helps !

Similar questions