Question

A man borrowed Rs. 4000 at a certain rate of interest and Rs. 5000 at 2% lower than the first. in all He paid Rs. 1050 as interest in 3 years. Find the two rates at which he borrowed the money.​

Answer 1

Answer:

B :} hope this helped

Step-by-step explanation:

Correct option is B)

For the first two years,

Amount =40000+  

100

40000×8×2

​

=40000+6400= Rs. 46400

Let x be the principal for the last 3 years.

Then, x+  

100

x×8×3

​

=35960

⇒x+

25

6x

​

=35960

⇒

25

25x+6x

​

=35960

⇒

25

31x

​

=35960

⇒x=

31

35960×25

​

= Rs. 29000

∴ Amount paid back after the second year = Rs. 46400− Rs. 29000= Rs.17400.