Question

A man bought two TV sets for Rs 42500.He sold one at a loss of 10% and other at a profit of 10%. If the selling price of each TV set is same determine the cost price of each set.

Answer 1

Answer:

Cost Price of First set = ₹19125

​Cost Price of Second set = ₹23375

Step-by-step explanation:

Given : A man bought two TV sets for Rs 42500.He sold one at a loss of 10% and other at a profit of 10%.

To find : If the selling price of each TV set is same determine the cost price of each set?

Solution :

Total cost of 2 TV sets = ₹42500

​Let the cost of First TV set be x

Then,

Cost of second TV set = ₹(42500-x)

Selling price of First TV set is

$SP_1= x+10\% \text{ of } x\\\\SP_1= \frac{110x}{100}$

Selling price of second TV set is

$SP_2= 42500-x-10\% \text{ of }(42500-x)\\\\SP_2= \frac{90(42500-x)}{100}$

S.P of First TV set = S.P of Second TV set

$\frac{110x}{100}=\frac{90(42500-x)}{100}$

$11x=90(42500-x)$

$11x=382500-9x$

$20x=382500$

$x=19125$

Therefore, Cost Price of First set = ₹19125

​Cost Price of Second set = ₹23375

Answer 2

Answer:

Step-by-step explanation:

Given : A man bought two TV sets for Rs 42500.He sold one at a loss of 10% and other at a profit of 10%.

To find : If the selling price of each TV set is same determine the cost price of each set?

Solution :

Total cost of 2 TV sets = ₹42500

​Let the cost of First TV set be x

Then,

Cost of second TV set = ₹(42500-x)

Selling price of First TV set is

Selling price of second TV set is

S.P of First TV set = S.P of Second TV set

Therefore, Cost Price of First set = ₹19125

​Cost Price of Second set = ₹23375