In rectangle. ABCD where diagnol AC and BD intersect at P if angle BPC = 124 degree Calculate angle BAP AND ADP
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hi friend
here your answer looking for
BPC = APD ( vertically opposite angle )
APD = 124
IN TRIANGLE. APD
DAP = ADP. ( OPPOSITE ANGLE OF ISO TRIANGLE )
DAP+ ADP + APD =180
ADP + ADP +124 =180
ADP = 28
AND, IN RECTANGLE ABCD
DAB = DAP + PAB
90 = 28 + PAB
PAB = 62
SO, BAP = 62
AND, ADP = 28
HOPE IT'S HELPFUL TO YOU
FOR FURTHER HELP CONTACT ME
FROM BRAINLY STAR Amaytripathi19
here your answer looking for
BPC = APD ( vertically opposite angle )
APD = 124
IN TRIANGLE. APD
DAP = ADP. ( OPPOSITE ANGLE OF ISO TRIANGLE )
DAP+ ADP + APD =180
ADP + ADP +124 =180
ADP = 28
AND, IN RECTANGLE ABCD
DAB = DAP + PAB
90 = 28 + PAB
PAB = 62
SO, BAP = 62
AND, ADP = 28
HOPE IT'S HELPFUL TO YOU
FOR FURTHER HELP CONTACT ME
FROM BRAINLY STAR Amaytripathi19
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